Calculate the bandwith.

redskry

Hi everybody !

I'm doing a game with photon and i'm trying to calculate the bandwith but i'm a little scare about the result..

Photon give 3GB /CCU ( user), so i take this number to "base"

My player sent his position 5 times per second. I only need the X and the Z value + 2 other int.
I round the position to 2 number aftter decimal to optimize the bandwith , so when i call the RPC to send position it's look likes this :

public void SendMove(float x, float y, int Test, int test2) { this.photonView.RPC("SendEnemyMoveRPC", PhotonTargets.All, x, y, test, test2); }
So around 13octet or 104Bits with this exemple : ( 1.56/2.53/5/8)

With 5 messages per second, it's equal to = 520bits/s

3.000.000bits / 520bits = 5.769 message in the month...

it's not enought at all right ? per day, a player can send 192 message ..
How it's possible ?

So i post it because i don't know if i'm doing something wrong? i don't know how i can more optimize my game to send less data..

So thanks if someone can show me a other way, i take all at this time ^^'!

Have a good day !

JohnTube

Hi @redskry,

I think your math is wrong.

First, 3GB (Gigabyte converted to bits) is 24^9bits: 24000000000bits (or 25769803776bits if 1kB is 1024b)

So around 13octet or 104Bits with this exemple : ( 1.56/2.53/5/8)

How did you count this?

With 5 messages per second, it's equal to = 520bits/s

Let's assume everything is fine up to this point.

3.000.000bits / 520bits = 5.769 message in the month...

This is wrong: 5769 is how many seconds in the month a player can keep sending messages with fixed size (104bits) at the same rate (5/second) without exceeding bandwidth.

Also, you are only considering messages from client to server and not server to client(s).

Take a look at the answer to the following question on our FAQ page:
How do I calculate traffic consumed by a user?

[Deleted User]

Hi @redskry,

3 GB is not the same as 3.000.000 bit.
3 GB = 3,072 MB = 3,145,728 KB = 3,221,225,472 Byte = 25,769,803,776 bit

So following your example with 520 bit usage per second, the result is 49,557,314 messages per month, which is significantly more.

redskry

Oh damn... night owl is not good for me .. Sorry too have loose your time !

But thanks so much ! It's save me !

redskry

Last 2 Question ^^, When i put some parameter in my RPC , like int[5], it's the equivalent to put 5 int parameters individualy ?

And the last , when a player send a message , to calculate the bandwith i have to know the number of player that i want to send ?
In my precedent calcul ( totally wrong i know ^^' ) i said that the player send 520 bit /s
but if 5 other player are in the room , i have to calculate the bandwith * 5? so 520*5 /s ?

Have a good day !

JohnTube

Hi @redskry,

To calculate the size of data serialized by Photon's binary protocol, go to this page.

For arrays the formula is:

4 + photon_sizeof(elements) - length * type_info(T)

So for int[5] (array of integers of length 5):
4 + (5 * 5) - 5 * 1 = 24bytes.

but if 5 other player are in the room , i have to calculate the bandwith * 5? so 520*5 /s ?

if you send to others then you should multiply by 5 but if you send to all including yourself then you should multiply by 6.

- 5 players in the room.
- target: others only.
- average message size is 24 bytes.
- 5 messages per second.
- an average player spends H hours per month on your game.

bandwidth/CCU/month = 24 * 5 * 5 * H * 60 (minutes per hour) * 60 (seconds per minute)

redskry

Great ! perfect anwser ! Thanks again and have a good continuation !:)

EDIT ; Sorry , but i just want to be sur ^^

- 8 players in the room.
- target: others only.
- average message size is 550 bits.
- 5 messages per second.
- an average player spends H "90"( just to be good for the worst case) hours per month on your game.

550 *8*8*90*60*60 = "11.404.800.000"

So , i'm 2 times less than i can use ?

JohnTube

550 * 5 * 8 * 90 * 60 * 60 = 7128000000bits/CCU/month.
Yes it's less than the free 3GB/CCU/month.